We connect a LinearMotion FB [a Clock FB] to rotate the Rocker with a constant angular velocity. This Step helps to understand:
The Machine Speed Setting is 60RPM, or 1Cycle/second. 1Cycle/second = 2π radians/second. The mechanism below shows the forces that act at the PinJoint. 

Addition of Vertical Forces acting on the Rocker [Point 2] : [↑+ve]. ∑FV=0 : R2V[N]  1[kg]*9.807[m/s/s] = 0; R2V = 9.807N [upwards] Addition of Horizontal Forces acting on the Rocker [Point 2] : [→ +ve]. ∑FV=0 : +R2H[N] + 1[kg]*0.1[m]*[2π]2[1/s/s] = 0; R2H = 3.948N [to the left] Moments are:


The image to the left is the same as the image above. I have added to the image the Horizontal and Vertical Force Vectors that ACTON the Rocker The two components are:
The forces are perpendicular[⊥] when the Rocker is horizontal. Hence, we can use Pythagoras, to give 10.571N Ftotal = √(Fg2 + Fc2) (Total Force = SQRT(SQR(Gravitation Force) + SQR(Centripetal Force)) = SQRT((m.g)2 + (m.r.ω2)2) Total Force = √((1*g)2 + (1*0.1*(2π)2)2) = √(9.812 + 3.9482) = 10.571N 