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It is continuous in Position, Velocity and Acceleration We construct this Throw segment with two Flexible Polynomial segments. Usually, the segments have an equal duration, but this is not necessary. Continuity at the MidPoint At the midpoint, the Position is at its maximum and the Velocity is zero. At the midpoint, Acceleration is finite and negative. At the midpoint, Jerk is continuous and zero. Position, Velocity, Acceleration, and Jerk are Continuous at the MidPoint. The Throw MotionLaw is QuickReturn because it has a negative acceleration at its maximum displacement. See Also: •Quick Return: Zero Jerk @ Start/End/MidPoint •Rapid Return: Finite Jerk @ Start/End/MidPoint •Rapid Return: SmoothStart/End Two Segment 'QuickReturn Motion 1'
Rise Segment Only
